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4a^2+27a+44=0
a = 4; b = 27; c = +44;
Δ = b2-4ac
Δ = 272-4·4·44
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-5}{2*4}=\frac{-32}{8} =-4 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+5}{2*4}=\frac{-22}{8} =-2+3/4 $
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